Post a New Question


posted by .

Use Newton's method to approximate a root of the equation 3sin(x)=x as follows.
Let x1=1 be the initial approximation.
The second approximation x2 is
and the third approximation x3 is

I got x2=-1.454
but can't get x3 :(

  • calculus -

    You are on the right track!
    eventually it will settle on x=-2.28.

    Remember that in the case of multiple roots, the one obtained by Newton's method is very dependent on the initial approximation. I assumed x1=1 is in radians.

  • calculus -

    I agree with drwls's setup in
    Newton's method

    starting with x1=1 I also got
    x2= -41.454 but then I got the next values as

    x3 = -3.787
    x4 = -2.1404
    x5 = -2.2878
    x6 = -2.1813
    x7 = -2.283
    appears to converge to around x = -2.28
    3sin(-2.28) = -2.2766

  • calculus -

    there was supposed to be a reference to
    drwls setup in

    As you can see in MathMate's reply both of our results coincide.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question