Math
posted by Johnny .
A spherical balloon expands when it is taken from the cold outdoors into a warm house. If the surface area increases by 50% (factor of 1.50), by what percentage does the radius of the balloon change?
a)7.7%
b)50%
c)100%
d)75%
e)22%

radius is proportional the square root of area.
R2/R1 = sqrt(A2/A1)
relaive change = (R2  R1)/R1
= (R2/R1)  1
sqrt(1.50)  1 = 0.2247 = 22.47%
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