Math: Word Problem
posted by Amy~ .
A ball is thrown upward from the top of a building which is 96ft tall w/ Initial velocity of 80 ft per sec.
Distance s(ft) of ball from the ground after t sec is s=96+80t16t^(2)
1) how many sec. will the ball pass the top of the building when it is coming down?
How would I solve this?

set s(t) to 96 and solve.
96=96+80t16t^2
solve for t 
why would I set 96 for s(t) because that's the height of the building ?
but it's when the ball passes the top of the building
Also I tried solving it I got to
16t(t5)= 0 what should I do next 
I finished solving it. thank you

riddle: my ones number is double my tens number, I'am less than 70 and more than 60

A ball is thrown vertically upward with velocity 100ft/sec and height of building is 40ft what is maximum height reached by ball and what is velocity when ball hits the ground
Respond to this Question
Similar Questions

calculas
If a ball is thrown vertically upward from the roof of 48 foot building with a velocity of 80 ft/sec, its height after t seconds is s(t)=48+80t–16t2. What is the maximum height the ball reaches? 
Calculus
When a ball is thrown straight down from the top of a tall building, with initial velocity 30 ft/sec, the distance from the release point at time t in seconds is given by s(t)=16t^2+30t. If the release point is 300 ft above ground, … 
12th Grade Calculus
When a ball is thrown straight down from the top of a tall building, with initial velocity 30 ft/sec, the distance from the release point at time t in seconds is given by s(t)=16t^2+30t. If the release point is 300 ft above ground, … 
Algebra
If an object is thrown vertically upward with an initial velocity of v, from an original position of s, the height h at any time t is given by: h=16t^2+vt+s(where h and s are in ft, t is in seconds and v is in ft/sec) a ball is thrown … 
Algebra 2
If an object is thrown vertically upward with an initial velocity of v, from an original position of s, the height h at any time t is given by: h=16t^2+vt+s(where h and s are in ft, t is in seconds and v is in ft/sec) a ball is thrown … 
PreCalc
ball thrown vertically upward with an initial velocity of 80 ft per second. The distance s(in ft) of the ball from the ground after t seconds is s=80t16t^2. a. draw the illustration. b. for what time interval is ball more than 96 … 
Math
If a ball is thrown vertically upward from the roof of 48 foot building with a velocity of 80 ft/sec, its height after t seconds is s(t) = 48+80t16t^2 What is the velocity of the ball when it hits the ground? 
Math Calc
If a ball is thrown vertically upward from the roof of 48 foot building with a velocity of 112 ft/sec, its height after t seconds is s(t)=48+112t–16t^2. What is the maximum height the ball reaches "in ft"? 
math
a ball is thrown vertically upward from the top of a building 96 feet tall with an initial velocity 80 m/ sec .the distance s of the ball from the ground after t seconds is s= 96+80t4.9 t^2.after how many seconds does the ball strike … 
Maths quadratic equation
A ball thrown vertically from the top of a building 96m at initial velocity 80m/sec.the distance 's' of the ball of the ground after 't' second is s=96+80t4.5t^2. After how many seconds does the ball strike the ground...?