# Math: Word Problem

posted by .

A ball is thrown upward from the top of a building which is 96ft tall w/ Initial velocity of 80 ft per sec.
Distance s(ft) of ball from the ground after t sec is s=96+80t-16t^(2)

1) how many sec. will the ball pass the top of the building when it is coming down?

How would I solve this?

• Math: Word Problem -

set s(t) to 96 and solve.

96=96+80t-16t^2
solve for t

• Math: Word Problem -

why would I set 96 for s(t) because that's the height of the building ?
but it's when the ball passes the top of the building

Also I tried solving it I got to
-16t(t-5)= 0 what should I do next

• Math: Word Problem -

I finished solving it. thank you

• Math: Word Problem -

riddle: my ones number is double my tens number, I'am less than 70 and more than 60

• Math: Word Problem -

A ball is thrown vertically upward with velocity 100ft/sec and height of building is 40ft what is maximum height reached by ball and what is velocity when ball hits the ground

## Similar Questions

1. ### calculas

If a ball is thrown vertically upward from the roof of 48 foot building with a velocity of 80 ft/sec, its height after t seconds is s(t)=48+80t–16t2. What is the maximum height the ball reaches?
2. ### Calculus

When a ball is thrown straight down from the top of a tall building, with initial velocity 30 ft/sec, the distance from the release point at time t in seconds is given by s(t)=16t^2+30t. If the release point is 300 ft above ground, …

When a ball is thrown straight down from the top of a tall building, with initial velocity 30 ft/sec, the distance from the release point at time t in seconds is given by s(t)=16t^2+30t. If the release point is 300 ft above ground, …
4. ### Algebra

If an object is thrown vertically upward with an initial velocity of v, from an original position of s, the height h at any time t is given by: h=-16t^2+vt+s(where h and s are in ft, t is in seconds and v is in ft/sec) a ball is thrown …
5. ### Algebra 2

If an object is thrown vertically upward with an initial velocity of v, from an original position of s, the height h at any time t is given by: h=-16t^2+vt+s(where h and s are in ft, t is in seconds and v is in ft/sec) a ball is thrown …
6. ### Pre-Calc

ball thrown vertically upward with an initial velocity of 80 ft per second. The distance s(in ft) of the ball from the ground after t seconds is s=80t-16t^2. a. draw the illustration. b. for what time interval is ball more than 96 …
7. ### Math

If a ball is thrown vertically upward from the roof of 48 foot building with a velocity of 80 ft/sec, its height after t seconds is s(t) = 48+80t-16t^2 What is the velocity of the ball when it hits the ground?
8. ### Math Calc

If a ball is thrown vertically upward from the roof of 48 foot building with a velocity of 112 ft/sec, its height after t seconds is s(t)=48+112t–16t^2. What is the maximum height the ball reaches "in ft"?
9. ### math

a ball is thrown vertically upward from the top of a building 96 feet tall with an initial velocity 80 m/ sec .the distance s of the ball from the ground after t seconds is s= 96+80t-4.9 t^2.after how many seconds does the ball strike …