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At what projection angle will the range of a projectile equal to 3 times its maximum height?

  • phy -

    The range is 2(V^2/g)*sinA cosA.

    The maximum height is (V^2/2g) sin^2A

    If range = 3 x (max height),
    2sinA cosA = (3/2) sin^2A, and
    4/3 = tan A

    A = 53.1 degrees

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