Physics
posted by Bob .
A long jumper jumps at a 45 degree angle towards the right bank which is 10.0 m away horizontally and 2.5 m vertically below. How long, or short, of the opposite bank will she land?

I assume she jumps at 45° above horizontal.
Is her initial velocity given by the question? 
No, the initial velocity has to be solved for.

ANSWER:
Vo = 9.0 m/s
She lands 0.21 m past the opposite bank
I'm not sure how to get those numbers, though. 
How far a long jumper gets obviously depends upon the takeoff speed. Unless you know what that is, you cannot say if she comes up short or not.

I just said the takeoff speed is 9.0 m/s.

I'm not sure either.
I have three unknowns (x, t and u =initial velocity), and two equations:
x=ucos(θ)t
y=usin(θ)t(1/2)gt²
unless I am missing something.
In any case, if I substitute u=9 m/s, I get the horizontal distance as 10.27, which is 0.27m past the other bank (and not 0.21). 
I thought you said that the takeoff speed has to be found (unknown).

You do have to solve for the takeoff speed, but I have the answers. I just don't know the procedure for solving the problem.

Neither do I when there are three unknowns and two equations. Sorry.