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how do i solve
X2 +4X-60

(the 2 after the x is supposed to stand for squared.)

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x^2+4x-60=0
You have to look for two numbers that multiply to the last term (-60) and add to the middle term (4). In this case, the numbers are 10 and -6. We write them like this:
(x+10)(x-6)
Check my work.

2x + 4x=60
6x=60
x=60/6
so x=10
very simple.....

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