how do i solve
X2 +4X-60
(the 2 after the x is supposed to stand for squared.)
Please type your subject in the School Subject box. Any other words, including obscure abbreviations, are likely to delay responses from a teacher who knows that subject well.
x^2+4x-60=0
You have to look for two numbers that multiply to the last term (-60) and add to the middle term (4). In this case, the numbers are 10 and -6. We write them like this:
(x+10)(x-6)
Check my work.
2x + 4x=60
6x=60
x=60/6
so x=10
very simple.....
To solve the quadratic equation X^2 + 4X - 60, you can use the quadratic formula or factor it. Let's start by factoring the equation.
1. Write the equation in the form of (X + a)(X + b) = 0.
X^2 + 4X - 60 = (X + a)(X + b)
2. Find two numbers, a and b, that add up to 4 (the coefficient of X) and multiply to -60 (the constant term).
The numbers are 6 and -10 since 6 + (-10) = 4 and 6 * (-10) = -60
3. Rewrite the equation using the found numbers:
X^2 + 10X - 6X - 60 = 0
4. Group terms and factor by grouping:
(X^2 + 10X) + (-6X - 60) = 0
X(X + 10) - 6(X + 10) = 0
Now combine like terms:
(X - 6)(X + 10) = 0
5. Set each factor equal to zero and solve for X:
X - 6 = 0 or X + 10 = 0
Solve each equation:
X = 6 or X = -10
So, the solution to the quadratic equation X^2 + 4X - 60 is X = 6 or X = -10.