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Solve algebraically and check

y = x^2 - 3
x + y = -1

  • equation -

    y appears in both equations to the first degree. You can eliminate y by equating the value of y from each equation.
    Solve the resulting quadratic equation for x.
    Back-substitute the values of x into the equations to get the corresponding values of y.

  • equation -

    Substitute x^2 - 3 for y in the second equation.

    x + x^2 - 3 = -1

    x^2 + x - 2 = 0

    (x + 2)(x - 1) = 0

    Find the two possible values for x and insert to find y. Insert both sets of values into second equation to check.

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