2x^2+6x-16 and 14x^2-3x-2
What factors does 14 have that can be combined with factors of -2 to add/subtract to get the middle
value?
14x^2-3x-2 = (7x + 2)(2x - 1)
I cannot find the factors for 2x^2 + 6x - 16. Are you sure you don't have a typo?
x^2 + 6x - 16 = (x + 8)(x -2)
To find the sum of these two polynomials, we need to add their like terms.
Let's first rewrite the polynomials in standard form, which is ordered from highest to lowest degree of the variable:
- The first polynomial, 2x^2 + 6x - 16, is already in standard form.
- The second polynomial, 14x^2 - 3x - 2, needs to be rearranged: 14x^2 - 3x - 2.
Now, let's combine like terms by adding the coefficients of the same degree terms:
(2x^2 + 14x^2) + (6x - 3x) + (- 16 - 2)
This simplifies to:
16x^2 + 3x - 18
Therefore, the sum of the given polynomials is 16x^2 + 3x - 18.