if you can answer these question and give the calculation that would be a great help thank you
1. Calculate the amount of storage required for a black and white bit-mapped graphic which has a resolution of 2000 x 1400 dpi.
2. calculate the amount of storage required for a 600 dpi black and white bit-mapped grphic which is 6 inches by 4 inches.
3.Describe how a graphic is stored using the bit map method
thanks again :D
1. To calculate the amount of storage required for a black and white bit-mapped graphic with a resolution of 2000 x 1400 dpi, we need to consider the number of pixels in the image and how many bits are used to represent each pixel.
First, let's calculate the number of pixels in the image:
Number of pixels = Width (in dots) x Height (in dots)
Number of pixels = 2000 x 1400 = 2,800,000 pixels
Next, we need to determine how many bits are used to represent each pixel. In a black and white bit-mapped graphic, each pixel is either black or white, which can be represented by a single bit (0 or 1).
Therefore, the amount of storage required for this black and white bit-mapped graphic will be:
Storage required = Number of pixels x Number of bits per pixel
Storage required = 2,800,000 pixels x 1 bit/pixel
Storage required = 2,800,000 bits
2. To calculate the amount of storage required for a 600 dpi black and white bit-mapped graphic with dimensions of 6 inches by 4 inches, similar steps can be followed.
First, convert the dimensions of the image to dots:
Width (in dots) = Width (in inches) x Resolution (in dots per inch)
Width (in dots) = 6 inches x 600 dpi
Width (in dots) = 3600 dots
Height (in dots) = Height (in inches) x Resolution (in dots per inch)
Height (in dots) = 4 inches x 600 dpi
Height (in dots) = 2400 dots
Next, calculate the number of pixels in the image:
Number of pixels = Width (in dots) x Height (in dots)
Number of pixels = 3600 dots x 2400 dots
Number of pixels = 8,640,000 pixels
Since this is a black and white bit-mapped graphic, each pixel can be represented by a single bit.
Therefore, the amount of storage required for this 600 dpi black and white bit-mapped graphic will be:
Storage required = Number of pixels x Number of bits per pixel
Storage required = 8,640,000 pixels x 1 bit/pixel
Storage required = 8,640,000 bits
3. In the bit map method, a graphic is stored by dividing it into a grid of small units called pixels. Each pixel represents a specific color or shade of gray. For black and white bit-mapped graphics, each pixel can have only two values: black (usually represented by a 0) or white (usually represented by a 1).
The graphic is represented by a series of binary code, where each binary digit (bit) corresponds to the value of a pixel. The binary code is stored in a continuous sequence in memory or storage.
To display or reproduce the graphic, the binary code is interpreted, and each pixel's value is determined, allowing the graphic to be recreated on a display or printed on paper.
1. To calculate the amount of storage required for a black and white bit-mapped graphic with a resolution of 2000 x 1400 dpi, we need to consider the size of each pixel.
First, let's determine the number of pixels in the image:
Total number of pixels = Width (in dpi) x Height (in dpi)
= 2000 x 1400
Since the image is black and white, each pixel only requires 1 bit to represent it. Therefore, we can now calculate the storage required in bits:
Total storage (in bits) = Total number of pixels x 1
= (2000 x 1400) bits
If you want to convert the storage to another unit of measurement, such as bytes or kilobytes, you can divide the number of bits by the appropriate conversion factor.
2. To calculate the amount of storage required for a 600 dpi black and white bit-mapped graphic that is 6 inches by 4 inches, we follow a similar process.
First, convert the inches to pixels by multiplying the dimensions by the resolution:
Width (in pixels) = 6 inches x 600 dpi
Height (in pixels) = 4 inches x 600 dpi
Next, calculate the total number of pixels:
Total number of pixels = Width (in pixels) x Height (in pixels)
Since the image is black and white, each pixel requires 1 bit. Thus, the storage required in bits will be:
Total storage (in bits) = Total number of pixels x 1
If you wish to convert the storage to a different unit, divide the number of bits by the appropriate conversion factor.
3. The bit map method is a way to store and represent images using binary values (0s and 1s). In a bitmap, each pixel of an image is assigned a specific binary value that corresponds to its color or intensity.
To store an image using the bitmap method, the computer creates a grid of pixels that corresponds to the resolution of the image. Each pixel is given a specific value based on whether it represents a particular color or intensity. In the case of a black and white bitmap, each pixel is either black (represented by 0) or white (represented by 1).
The computer then stores these binary values sequentially, which forms the bitmap representation of the image. Each row of the image is stored one after another, and each pixel within a row is stored one after another as well. This sequential storage allows for easy access and retrieval of the image data.
When retrieving the stored image, the computer reads the binary values and interprets them to display the corresponding colors or intensities, thereby recreating the original image.
This method of storing images allows for efficient storage of black and white images, as each pixel only requires a single bit of storage. However, it may require more storage space for images with higher color depths or resolutions, as each pixel would require more bits to represent its color or intensity.