x = 3

-2x^(2) / (1/3)^(-x)

how to solve?

would I multiply 3(-2) than square?
Also, when I move (1/3)^(-3) to the numerator would it become (3)^3

-2x^(2) / (1/3)^(-x)

when x = 3 I get

-2(9)/(1/3)^-3
= -18(1/3)^+3
= -18(1/27)
= -2/3