I need to see how to arrange 8-1/5y=10x to mx+b form Is it -1/5y=10x-8? I need the slope and y intercept. Thanks much to who ever helps me. Can anyone show me how to work this?

8 -

8 -(1/5)y = 10x
Solve for y:
-y/5 = 10x - 8,
Multiply both sides by -s:
y = -50x + 40
Slope = -50
y-int. = 40


9

To solve the equation 8 - 1/5y = 10x for y in the slope-intercept form (y = mx + b), you need to isolate the term containing y.

Let's start by simplifying the equation:

8 - 1/5y = 10x

First, we'll eliminate the fraction by multiplying through by 5:

5(8 - 1/5y) = 5(10x)

40 - y/5 = 50x

Next, let's isolate the term containing y by subtracting 40 from both sides:

40 - y/5 - 40 = 50x - 40

-y/5 = 50x - 40

Now, let's multiply through by -1/5 to get y by itself:

(-1/5)(-y/5) = (-1/5)(50x - 40)

y/5 = -10x + 8

Finally, multiply through by 5 to get rid of the fraction:

5(y/5) = 5(-10x + 8)

y = -50x + 40

Now the equation is in the slope-intercept form: y = mx + b, where the slope (m) is -50 and the y-intercept (b) is 40.