An aircraft manufacturer determines that one of it's aircrafts has twice as many seats as another. Find the number of seats for each aircraft if the total number of seats is 336.
336 / 3 = ?
1st aircraft has x seats,
2nd aircraft has 2x seats,
x + 2x = 336
3x = 336
x = 112 seats,
2x = 2 * 112 = 224 seats.
To solve this problem, let's assume that the number of seats in the smaller aircraft is x. According to the information given, the larger aircraft has twice as many seats as the smaller one.
So, the number of seats in the larger aircraft is 2x.
We are also given that the total number of seats in both aircraft is 336. Therefore, we can write the equation:
x + 2x = 336
Combining like terms, we get:
3x = 336
To solve for x, divide both sides of the equation by 3:
x = 336 / 3
x = 112
So, the smaller aircraft has 112 seats.
To find the number of seats in the larger aircraft, multiply x by 2:
2x = 2 * 112
2x = 224
Therefore, the larger aircraft has 224 seats.
In conclusion, the smaller aircraft has 112 seats, and the larger aircraft has 224 seats.