A sulfuric acid solution containing 571.6g of H2SO4 per of solution has a density of 1.329g/cm3. Calculate (a) mass percentage
(b)mole fraction (c) molality (d) molarity of H2SO4 in this solution.
A sulfuric acid solution containing 571.6g of H2SO4 per ????
sorry about that it's A sulfuric acid solution containing 571.6g of H2SO4 per L of solution
Nevermind I figured it out
How
I have a same problem on our assignment. I am confused on the question. How you figured it out?
To calculate the mass percentage, mole fraction, molality, and molarity of H2SO4 in the given sulfuric acid solution, we can use the following formulas:
(a) Mass Percentage:
Mass Percentage = (mass of solute / mass of solution) × 100
(b) Mole Fraction:
Mole Fraction = (moles of component / total moles of all components)
(c) Molality:
Molality = (moles of solute / mass of solvent in kg)
(d) Molarity:
Molarity = (moles of solute / volume of solution in liters)
Let's calculate each parameter step by step:
(a) Mass Percentage:
In order to calculate the mass percentage, we need to determine the mass of the solute (H2SO4) and the mass of the solution.
Given:
Mass of H2SO4 (solute) = 571.6 g
Density of solution = 1.329 g/cm^3
First, we need to determine the volume of the solution.
Density = Mass / Volume
Volume = Mass / Density
Volume = 571.6 g / 1.329 g/cm^3
Convert g/cm^3 to g/mL (1 cm^3 = 1 mL):
Volume = 571.6 g / 1.329 g/mL = 429.8 mL
The mass of the solution is the same as the mass of the solute in this case.
Mass Percentage = (571.6 g / 571.6 g) × 100
Mass Percentage = 100%
(b) Mole Fraction:
To calculate the mole fraction, we need to determine the moles of H2SO4 and the total moles of all components.
To find the moles of H2SO4, we need to convert the given mass of H2SO4 to moles using the molar mass of H2SO4.
Molar mass of H2SO4 = (2 × atomic mass of H) + atomic mass of S + (4 × atomic mass of O)
Molar mass of H2SO4 = (2 × 1.0 g/mol) + 32.1 g/mol + (4 × 16.0 g/mol)
Molar mass of H2SO4 = 98.1 g/mol
Moles of H2SO4 = mass of H2SO4 / molar mass of H2SO4
Moles of H2SO4 = 571.6 g / 98.1 g/mol = 5.82 mol
The total moles of all components are just the moles of H2SO4 since it is the only component.
Mole Fraction = (5.82 mol / 5.82 mol) = 1.00
(c) Molality:
To calculate the molality, we need to determine the moles of H2SO4 and the mass of the solvent (which is the solution mass - solute mass).
Mass of solvent = mass of solution - mass of solute
Mass of solvent = (571.6 g + 571.6 g) - 571.6 g
Mass of solvent = 571.6 g
Molality = moles of H2SO4 / (mass of solvent in kg)
Molality = 5.82 mol / (571.6 g / 1000) kg
Molality = 5.82 mol / 0.5716 kg
Molality = 10.16 mol/kg
(d) Molarity:
To calculate molarity, we need to determine the moles of H2SO4 and the volume of the solution. The volume of the solution in liters is the same as the volume calculated earlier (429.8 mL).
Molarity = moles of H2SO4 / volume of solution in liters
Molarity = 5.82 mol / (429.8 mL / 1000) L
Molarity = 5.82 mol / 0.4298 L
Molarity = 13.54 mol/L
So, the calculations yield:
(a) Mass Percentage = 100%
(b) Mole Fraction = 1.00
(c) Molality = 10.16 mol/kg
(d) Molarity = 13.54 mol/L