I have
- to graph each relation
- decide if it is a function
- state the domain and the range.
1) {(2,3),(4,-3),(5,1),(-1,3)}
how would I decide if something is a function in general?
I kind of remember the domain and the range,but since I did this 2 years ago I forgot. Is the domain the x and the range the y?
I found out about domain and range
how would I solve this then:
y=line x-3 line
y^2 = x
y = (x+1)/(x-3)
for those how would I get the domain and range
for y = sqrt x
the domain is like R something?
You need to look up your notes and your textbooks to review the chapter(s) on functions, domain and range.
The graph is an arrow graph that relates each member of the domain to the corresponding member in the range.
The domain contains the x-value of all the ordered pairs, and the range, the y-values.
To graph a relation, you would plot each point on a coordinate plane. In this case, the given relation is {(2,3),(4,-3),(5,1),(-1,3)}. So you would plot the points (2,3), (4,-3), (5,1), and (-1,3) on the coordinate plane.
To determine if a relation is a function, you need to check if each value in the domain (x-coordinate) is associated with exactly one value in the range (y-coordinate). In other words, for each x-value, there should be a unique y-value. If this condition is satisfied for all the points in the relation, then the relation is a function.
For the given relation, {(2,3),(4,-3),(5,1),(-1,3)}, all the x-values (2, 4, 5, -1) correspond to unique y-values (3, -3, 1, 3) respectively. Therefore, this relation is a function.
Regarding the domain and range, you are correct. The domain refers to the set of all possible x-values, and the range refers to the set of all possible y-values. In this case, the domain is {2, 4, 5, -1}, which are the x-values in the relation. The range is {3, -3, 1}, which are the y-values in the relation.
So, for the given relation, the graph would include the points (2,3), (4,-3), (5,1), and (-1,3). It is a function, and the domain is {2, 4, 5, -1}, while the range is {3, -3, 1}.