Post a New Question

PreCalc

posted by .

The area of a parking lot is 805 square meters. A car requires 5 square meters and a bus requires 32 square meters of space. At most 80 vehicles can park at one time. If the cost to park a car is $2.00 and the cost to park a bus is $6.00, how many buses should be in the lot to maximize income?

I'm given the choices 10, 15, or 28

  • PreCalc -

    You could set this up as a caldculaus problem and find the maximum-income number of buses, or just calculate and compare the income for each the three choices given.

    With 10 buses, you have 10x32 = 320 m^2 for buses and 805-320 = 485 m^2 for 485/5 = 97 cars. Total income is 60 + 194 = $254 . However, the number of vehicles exceeds tha allowed .

    With 15 buses, you have 480 m^2 for buses and 325 m^2 for 65 cars. The income is 90+130 = $220

    Now consider the case of 28 buses. Chances are the total income wil be less than the 15 bus case.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question