Math
posted by James .
Can someone please tell me what the vertex and line of symentry would be for r(x)=3(x+3)^2.. Thank you

F(x) = y = 3(x + 3)^2 + k.
Vertex Form:
y = a(x  h)^2 + k.
V(h , k) = V(3 , 0),
Line of sym = h = 3 = Xv.
h is positive in your Eq because you are subtracting a negative 3.
If you gave me the complete Eq, k = 0.
The graph opens downward since a is negative(3).