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Can someone please tell me what the vertex and line of symentry would be for r(x)=-3(x+3)^2.. Thank you

  • Math -

    F(x) = y = -3(x + 3)^2 + k.
    Vertex Form:
    y = a(x - h)^2 + k.
    V(h , k) = V(-3 , 0),
    Line of sym = h = -3 = Xv.
    h is positive in your Eq because you are subtracting a negative 3.
    If you gave me the complete Eq, k = 0.
    The graph opens downward since a is negative(-3).

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