Q=50-5P. Solve the equation for P

Choose the right one

P=50-Q

P=50+Q

P=10-5Q

P=10-(1/5)Q

P=50-5Q

If you plot P on the horizontal (x) axis, and Q on the vertical (y) axis, then the slope is -(1/5).

q=50-5P

subtract 50
q-50=-5P
divide by -5

-1/5q-50/-5=P
-1/5Q+10=P

so it's the fourth answer.

Thank You, I thought that was but not 100% sure because I get backwards on the positive and negatives, Do you know how I find out the slope of the line or would graph it then?

so it is negative then? -(1/5) Thank You

To solve the equation for P, you need to isolate the variable P on one side of the equation:

Given equation: Q = 50 - 5P

Step 1: Start by moving the constant term (-5P) to the opposite side of the equation.
Q + 5P = 50

Step 2: Now, move the variable Q to the opposite side of the equation.
5P = 50 - Q

Step 3: To isolate P, divide both sides of the equation by 5.
P = (50 - Q) / 5

Therefore, the correct equation is:
P = (50 - Q) / 5