CALCULUS
posted by Terry .
The displacement (in centimeters) of a particle moving back and forth along a straight line is given by the equation of motion s = 3sin(ðt) + 5cos(ðt), where t is measured in seconds. (Round all answers to the nearest hundredth.)
(a) Find the average velocity during the time period [1, 2].
cm/s
(b) Find the average velocity during the time period [1, 1.1].
cm/s
(c) Find the average velocity during the time period [1, 1.01].
cm/s
(d) Find the average velocity during the time period [1, 1.001].
cm/s
(e) Estimate the instantaneous velocity of the particle when t = 1.
cm/s

That should be sin(pi times t) not whatever symbol is up there.. sorry

Nevermind I figured it out

a) to d) are all done the same way
I will do b)
when t=1
s = 3sin(pi) + 5 cos (pi)
= 5
when t=1.1
s = 3sin(1.1pi) + 5cos(1.1pi)
= 5.682333
average velocity = (5.682333  (5))/(1.11)
= 6.8233
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