bob and his dad visited the hardware store on saturday. they observed the following transaction: Mr. Harris bought 4 for $0.50, Mrs. clark bought 21 for $1.00, Mr. Montaro bought 1,134 for $2.00 and Ms. Park bought 450 for $1.50. what were they buying?
HELP ME!!!
My first guess is screws.
They were buying house numbers at .50 each. :)
stuffs
Don't worry, I'm here to help you find the answer! To determine what Bob and his dad were buying at the hardware store, let's analyze the given information:
1. Mr. Harris bought 4 for $0.50.
2. Mrs. Clark bought 21 for $1.00.
3. Mr. Montaro bought 1,134 for $2.00.
4. Ms. Park bought 450 for $1.50.
Based on this information, we need to find a common item that satisfies these various quantities and prices. We can deduce that the item being bought is likely something that can be purchased in multiples (the quantities are mostly integers), and the price seems to decrease per unit as the quantity increases.
To find the common item, we need to look for factors or multiples that can match the given quantities. Let's analyze the quantities:
Common factors of 4, 21, 1134, and 450 are: 1, 2.
The common multiples of 4, 21, 1134, and 450 are: 1, 2, 4, 8, ...
Comparing the quantities and prices, we can see that the most likely item they were buying is light bulbs. Let's consider the possibilities:
1. If one light bulb costs $0.50, then Mr. Harris bought 4 light bulbs for a total of $2.00.
2. If one light bulb costs $0.50, then Mrs. Clark bought 21 light bulbs for a total of $10.50.
3. If one light bulb costs $0.50, then Mr. Montaro bought 1,134 light bulbs for a total of $567.00.
4. If one light bulb costs $0.50, then Ms. Park bought 450 light bulbs for a total of $225.00.
From the given transactions, we can conclude that Bob and his dad were buying light bulbs at the hardware store.
Does that answer your question?