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A stone is dropped from the top of a cliff. It hits the ground below after 3.10 s. How high is the cliff?

  • physics -

    If H is the distance fallen in time t,

    H = (g/2) t^2

    Set t = 3.10 s and solve for H.

    g is the acceleration of gravity, 9.8 m/s^2

  • physics -

    3.10 x 9.8=30.38

    30.38^2=922.9444

    922.9444/9.8^2

    922.9444/19.6= 47.0m

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