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Algebra

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How do I express this in algebraic form? And could you please explain how you came up with the expression?
"Come up with a number. Add 3 to it. Muliply by 1 more than the original number. Subtract 3. Divide by the original number. Subtract 4. You should get the original number.

How it works: x is the original number. Add 3 to x to get (x+3). Multiply by (x+1) to get x² + 4x + 3. Subtract 3 to get x² + 4x, which factorises to x(x+4). Dividing by the original number, x, gives x + 4, and subtracting 4 gives the original number, x."

  • Algebra -

    Is (x^2+4x/x)-4 correct?

  • Algebra -

    Come up with a number: x
    Add 3 to it : x+3
    Muliply by 1 more than the original number : (x+3)(x+1)
    Subtract 3 : (x+3)(x+1) - 3
    Divide by the original number : [(x+3)(x+1) - 3]/x
    Subtract 4 : [(x+3)(x+1) - 3]/x - 4

    [(x+3)(x+1) - 3]/x - 4
    = (x^2 + 4x +3 - 3)/x - 4
    = (x^2 + 4x)/x - 4
    = x + 4 - 4
    = x

    Notice the long expression follows the actual wording.
    Your answer of (x^2+4x/x)-4 needs brackets like this:
    (x^2+4x)/x - 4 or else only the 4x is divided by x

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