6x+5y=-4
3x-3y=9
A- 1,-2
B- 1,2
C- 2,-1
D- 3,-1
E- -1,2
6x + 5y = -4
3x - 3y = 9
Multiply each side of 1st Eq by -3 and 2nd Eq by 6 and add the 2 Eq:
-18x - 15y = 12
18x - 15y = 54
0 - 33y = 66
y = -2
Substitute -2 for y in fhe 2nd Eq:
3x -3 * -2 = 9
x = 1
(1 , -2).
Correction!
-18x - 15y = 12
18x - 18y = 54
To find the solution to the given system of equations:
6x + 5y = -4 ---(1)
3x - 3y = 9 ---(2)
You can solve this system of equations using the method of substitution, which involves solving one equation for one variable and substituting it into the other equation.
Let's solve equation (2) for x:
3x - 3y = 9
3x = 3y + 9 (added 3y to both sides)
x = (3y + 9) / 3
x = y + 3 ---(3)
Now, substitute equation (3) into equation (1):
6x + 5y = -4
6(y + 3) + 5y = -4 (substituted x from equation (3))
6y + 18 + 5y = -4 (distributed 6)
11y + 18 = -4 (combined like terms)
11y = -4 - 18
11y = -22
y = -22 / 11
y = -2
Substituting the value of y = -2 into equation (3) to find x:
x = y + 3
x = -2 + 3
x = 1
Therefore, the solution to the given system of equations is x = 1 and y = -2.
So, the correct answer is A- 1,-2.