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1. A Uniform rod AB 3m long weighing 3 Kg is held horizontally by two strong vertical strings at its ends. A weight of 7 kg is hanging on the rod at a distance of 1m from end A and another weight of 12 Kg is hanging at 0.5 m from end B.(a)Make the free body diagram of the rod and (b)Find the tension in two strings.

  • phy -

    you know the tension sum is equal to the weights.

    Ta+Tb-3*g-12*g-7g=0 where g is 9.8N/kg

    Then, sum moments about any point. I will sum at end a.

    1.5*3g -Tb*3+1*7*g+2.5*12g=0

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