A woman sells 18 containers of milk a day. Each container holds 22 quarts and a quart of milk weighs 1 1/2 pounds. If each of the cows give 25 pounds of milk a day, then at least how many cows must she have?
18 * 22 * 1.5 = ?? pounds
Divide the above answer by 25.
To find out how many cows the woman must have, we need to calculate the total amount of milk she sells in a day and then divide it by the amount of milk each cow gives in a day.
First, let's find out how many quarts of milk the woman sells in a day. We know that each container holds 22 quarts, and she sells 18 containers, so the total number of quarts of milk she sells is:
22 quarts/container * 18 containers = 396 quarts.
Next, we need to convert the quarts of milk to pounds. We know that 1 quart of milk weighs 1 1/2 pounds, so the total weight of the milk she sells is:
396 quarts * 1 1/2 pounds/quart = 594 pounds.
Lastly, we divide the total weight of the milk sold by the amount of milk each cow produces in a day. We know that each cow gives 25 pounds of milk, so the minimum number of cows required is:
594 pounds ÷ 25 pounds/cow ≈ 23.76 cows.
Since you can't have a fraction of a cow, the woman must have at least 24 cows to meet the demand for milk.