MATH 2B Calculus
posted by TOMO .
Consider the area between the graphs x+4y=14 and x+7=y^2. This area can be
computed in two different ways using integrals.
First of all it can be computed as a sum of two integrals
They ask to use two integrals so i put f(x) from 7 to 2 which is correct
but for g(x) i put 2 to 14 for some reason 14 is wrong. I also put
f(x)=sqrt(x+7) and g(x)= (14x)/4 and both are wrong wrong. I got
everything else correct except for these and I don't what I did wrong.

first, graph the two equations (in one cartesian plane)
then get the points of intersection:
x+7=y^2 *this is the second equation
x=y^27
substitute this to the first:
y^27+4y=14
y^2+4y21=0
(y+7)(y3)=0
y=7 and y=3
substitute these back to obtain corresponding values of x:
*if y=7,
x=(7)^27=42
*if y=3,
x=(3)^27=2
therefore, points of int are (42,7) and (2,3)
looking at the graph, i suggest you do vertical strips (that is, dx),, divide the whole area into region 1 (left side) and region 2 (right side),, after you do this, get the boundaries.
Region 1:
for x: the boundaries are the graph of the parabola (that is x=y^27) and the xcoord of the first point of int (x=2)
for y: since parabola is symmetric with respect to xaxis, y is from 3 to 3.
the area of region 1 is:
integral[from 3 to 3](integral[from y^27 to 2] dx)dy)
*note: this is double integral since A=dxdy
Region 2:
for region 2, i suggest you do horizontal strips (that is, dy) ,,then get the boundaries:
for x: from xcoord of first point of int (x=2) to xccord of 2nd point of int (x=42)
for y: from the parabola (y=sqrt(x+7)) to the line (y=(14x)/4)
the area of region 2 is:
integral[from 2 to 42](integral[from sqrt(x+7) to (14x)/4] dy)dx)
i'll leave the integration calculation to you,, add the areas and you'll finally get the whole area.
so there,, sorry for long explanation,,
i hope i was able to help,, =)
Respond to this Question
Similar Questions

Cal
consider the area between the graphs x+3y=1 and x+9=y^2. this area can be computed in two different ways using integrals. First of all it can be computed as a sum of two integrals where a=,b=,c= and f(x0= and g(x)=. Alterntaively this … 
Cal
consider the area between the graphs x+3y=1 and x+9=y^2. this area can be computed in two different ways using integrals. First of all it can be computed as a sum of two integrals where a=,b=,c= and f(x0= and g(x)=. Alterntaively this … 
CAL
consider the area between the graphs x+3y=1 and x+9=y^2. this area can be computed in two different ways using integrals. Please integral both ways both respect to x and to y. ANd please show your work and thank you 
Calculus
Consider the area between the graphs x+1y=12 and x+8=y2 . This area can be computed in two different ways using integrals First of all it can be computed as a sum of two integrals Interval a to b f(x)= i put 12x but it's wrong Interval … 
math, calculus 2
Consider the area between the graphs x+y=16 and x+4= (y^2). This area can be computed in two different ways using integrals. First of all it can be computed as a sum of two integrals integrate from a to b of f(x)dx + integrate from … 
MATH
Evaluate by writing it as a sum of two integrals and interpreting one of those integrals in terms of an area. 
Calculus Area between curves
Consider the area between the graphs x+6y=8 and x+8=y2. This area can be computed in two different ways using integrals First of all it can be computed as a sum of two integrals where a= , b=, c= and f(x)= g(x)= I found a, but not … 
Calculus Please Help4
Consider the area between the graphs x+2y=9 and x+6=y^2. This area can be computed in two different ways using integrals First of all it can be computed as a sum of two integrals as integral f(x)dx from a,b + integral g(x)dx from b,c … 
Calculus (math)
Consider the area between the graphs x+3y=35 and x+5=y2. This area can be computed in two different ways using integrals 
Calculus  Integrals
Consider the region enclosed by the graphs of x=y^25 and x=3y^2 a)Express the area of this region by setting up an integral with respect to x b) Express the area of this region by setting up an integral with respect to y c) Find …