Algebra 2
posted by Jessica .
Find the value of K so that the point P lies on the line L.
1. P(2,1), L: 3x + Ky = 8
2. P(2,2), L: Kx + (K + 1)y = 2
Help me i have no idea how to do this! :[

in your given point, the first number is the x value, the second number is the y value.
So just substitute.
3(2) + k(1) = 8
6 + k = 8
k = 2
Do the second one the same way, let me know what you got. 
Is this right?
k(2) + 2 = k(2) + 2
4k = 0
k = 0 
Your last two lines are correct, but how did you get your first line from the given equation
My line would have been
k(2) + (k+1)(2) = 2
then
2k + 2k + 2 = 2
leading to your last two lines.
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