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i need help with operation with polynomial---------------------

1) (x^2 + x - 6) / (x - 2)=

2) 24b^4C^3 / 6b^2c=

3) (3p^2 + pq - 2q^2)/ (p + q)=

  • math -

    1. (X^2 + X - 6) / (X - 2).
    Factor the trinomial:
    (X + 3)(X - 2) / (X - 2) =
    Cancel the (X - 2) factors:
    X + 3.

    2. 24b^4c^3 / 6b^2c = 4b^2c^2

    3. (3p^2 + pq - 2q^2) / (p + 2)
    Factor the trinomial using A*C Method:
    A * C = 3 * -2 = -6,
    3p^2 +3pq-2pq -2q^2
    Group the 4 terms into factorable
    pairs:
    3p^2+3pq -2pq-2q^2,
    3p(p + q) -2q(p + q),
    Factor out (p + q):
    (p + q) (3p - 2q) / (p + q),
    CANCEL THE (P + q) factors:
    3p - 2q.

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