assuming that 1g of aspirin dissolves in 450ml of water at 10°C,how much aspirin would be lost in the 5ml of water added to the reaction mixture if the mixture were at 10°C during filtration?
I don't understand the symbolism at the 10 oC (the A with a mark over it)but if that is actually 10 C, then 5 mL will lose 1 g x (5/450)= ??g
DR i can't see what you wrote here
dr i can't see what you wrote here
My symbolism isn't much better. I forgot to turn off the superscript. I'll try again.
I have trouble reading the letter A with a mark over it after the 10.
I assume that is just 10 oC.
1 g x (5 mL/450 mL) = ?? solubility in 5 mL water.
fiyhu
To determine how much aspirin would be lost in the additional 5ml of water added to the reaction mixture during filtration, we need to find out the maximum amount of aspirin that can dissolve in 5ml of water at 10°C.
Based on the information provided, we know that 1g of aspirin dissolves in 450ml of water at 10°C. Therefore, we can calculate the amount of aspirin that can dissolve in 1ml of water using a proportion:
1g of aspirin / 450ml of water = x g of aspirin / 1ml of water
Solving this proportion, we find that x = 1g / 450 = 0.0022g
So, 0.0022g of aspirin can dissolve in 1ml of water at 10°C.
Now, to find out the maximum amount of aspirin that can dissolve in 5ml of water at 10°C, we multiply the amount that can dissolve in 1ml (0.0022g) by 5:
0.0022g/ml * 5ml = 0.011g
Therefore, the maximum amount of aspirin that can dissolve in the additional 5ml of water at 10°C is 0.011g.
If the mixture were at 10°C during filtration, this would be the maximum amount of aspirin that could potentially be lost in the 5ml of water added to the reaction mixture.