posted by jacob .
The height of a rocket in meters t seconds after it is launched is approximated by the polynomial 0.5 at2 + vt + y where a is always -9.8, v is the initial velocity, and h is the initial height. A 300X was launched from a height of 10 meters. What was its height after 3 seconds?
Height(t) = -4.9t^2 + vt + 10
so Height(3) = -4.9(9) + 3v+10
= 3v - 34.1
You will have to know v, the intital velocity, to find to find an actual numerical answer.