Math
posted by Jaimie .
lim (as x approaches infinity) (x^21)/(x^2+1)
How would you solve that by using algebra?
I can simplify the above because it is difference of squares. But then what about the bottom

just multipy numerator and denominator by 1/x^2
lim (x^2/x^2 1/x^2)/(x^2/x^2+1/x^20=
lim (11/x^2)/(1+1/x^2)=1