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it is 0.1M of acetic buffer equal to sum up of 0.05M of acetic acid and 0.05M of sodium acetic ?
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Calculate the amount (in mL) of 1.520M NaOH that is required to add the following acetic acid solution to prepare a buffer with
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You had this in math. It isn't chemistry. 5.75 = 4.74 + log b/a 1.01 = log b/a 10^(b/a) = 1.01 Plug
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Calculate the amount (in mL) of 1.520M NaOH that is required to add the following acetic acid solution to prepare a buffer with
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I would do this. 5% w/v means 5g HAc/100 mL solution which is (5/60) mols/100 and that is 5/60/0.1L
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You want to make an acetic acid/acetate buffer, pH 3.8, with a volume of 250 mL, and a final concentration of ([AcOH] + [AcO-])
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You need to look up pKa for acetic acid in your text or notes. I used pKa = 4.74. And is that 3.8 or
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If you have 200 ml of a 0.1M solution of acetic acid (pka=4.75),
1. How many ml of a solution of 1.O M NaOH would you need to
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200 mL x 0.1M = 20 mmoles. 1. ............HAc + OH^- ==> Ac^- H2O initial.....20.0...0........0
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Starting with 1.0M acetic acid and 0.50M NaOH, how would you prepare 100ml of 0.10M acetate buffer , pH =4.50? pKa of acetic
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I don't knw it. Buh pls m interested In d solution
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How would you prepare 30 mL of acetic acid/acetate buffer solution of pH = 5.06?. Assumeyou have 0.1M solutions of both acetic
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If we knew the molarity you wanted for the buffer we could calculate it. I suppose not knowing the M
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An acetic acid buffer solution is required to have a pH of 5.27. You have a solution that contains 0.01 mol of acetic acid. How
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To calculate the number of moles of sodium acetate needed to add to the acetic acid solution, we
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Calculate the volume of 1.00 M acetic acid solution and mass of sodium acetate needed to make 250 mL of a 0.450 M acetic
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I worked this below. I'll try to find it and give you a link.
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Calculate the volume of 1.00 M acetic acid solution and mass of sodium acetate needed to make 250 mL of a 0.450 M acetic
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I work these buffer problems with millimols instead of M. You want 250 mL x 0.450M = 112.5 millimols
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A chemist wants to be a supercook and wants to create 8%(m/v) acetic acud solution to be "extra strength" vinegar. if pure
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8% m/v means 8 g acetic acid/100 mL soln. You want 500 mL soln so you want 5*8 = 40 g acetic acid.
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