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algebra

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A chemist mixes some 20% acid solution with pure 100% acid to increase the concentration. How much pure acid and acid solution should be mixed to form 100 milliliters of 40% acid solution?

  • algebra -

    first, represent:
    let x = amount of 20% acid used (in mL)
    let 100-x = amount of 100% acid used (since the total volume of the 2 acids mixed must be 100)

    therefore,
    0.2x + 1(100-x) = .4(100)
    *note: 0.2 = 20%, 1 = 100%, .4=40%
    0.2x + 100-x = 40
    -0.8x=-60
    x = 75 mL of 20% acid, and
    100-x = 25 mL of 100% acid

    so there,, i hope i was able to help.. =)

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