calculate volume of co2 produced by combustion of 40 ml of acetone in presence of excess oxygen?
You need to know the density of the acetone in order to know the mass acetone taken. mass = volume x density.
1. Write the equation and balance it.
2. Convert mass acetone to moles. moles = grams/molar mass.
3. Using the coefficients in the balanced equation, convert moles acetone to moles CO2.
4. Convert moles CO2 to volume (I presume at STP?). moles x 22.4 = liters CO2 at STP.
calculate the volume of co2 produced by the combustion of 40 ml of acetone in the presence of excess of o2
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To calculate the volume of CO2 produced by the combustion of acetone, we first need to determine the balanced chemical equation for the reaction. The combustion of acetone can be represented by the following equation:
C3H6O + 4O2 -> 3CO2 + 3H2O
From the balanced chemical equation, we can see that for every 1 mole of acetone (C3H6O) combusted, 3 moles of CO2 are produced.
Given the volume of acetone (40 mL), we need to convert it to moles using the ideal gas equation, PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature. Assuming standard temperature and pressure (STP), which is 1 atmosphere (atm) and 273.15 Kelvin (K), we can calculate the number of moles of acetone.
Now, we need to find the volume of CO2 using the mole ratio from the balanced equation. Since every 1 mole of acetone produces 3 moles of CO2, the volume of CO2 will also be 3 times the volume of acetone.
Here are the steps to calculate the volume of CO2 produced:
1. Convert the volume of acetone from milliliters (mL) to liters (L) by dividing it by 1000.
Volume (L) = 40 mL / 1000 = 0.04 L
2. Calculate the number of moles of acetone using the ideal gas equation:
n = PV / RT, assuming STP where P = 1 atm and T = 273.15 K. The value of R is 0.0821 L*atm/(mol*K).
n = (1 atm * 0.04 L) / (0.0821 L*atm/(mol*K) * 273.15 K)
3. Multiply the number of moles of acetone by the mole ratio from the balanced equation.
Moles of CO2 = n * (3 moles CO2 / 1 mole acetone)
4. Convert the moles of CO2 to volume using the ideal gas equation at STP.
Volume of CO2 = n *RT / P, where P = 1 atm and T = 273.15 K.
Volume of CO2 = (n * 0.0821 L*atm/(mol*K) * 273.15 K) / 1 atm
Now, plug in the values and perform the calculations:
Volume of CO2 = [(0.04 L * 1 atm) / (0.0821 L*atm/(mol*K) * 273.15 K)] * (3 moles CO2 / 1 mole acetone) * (0.0821 L*atm/(mol*K) * 273.15 K) / 1 atm
After performing the calculations, you will get the volume of CO2 produced in liters.