Calculate the number of grams of water produced from 30 g of oxygen gas. List only the number of grams of water. First, you will need to balance the equation above. Round to the nearest hundredth. And, as always, don't forget the units.C6H10+O2---->CO2+H2O

1. Write the equation and balance it.

2. Convert 30 g oxygen to moles. moles = grams/molar mass
3. Using the coefficients in the balanced equation, convert moles oxygen to moles water.
4. Convert moles H2O to grams. g = moles x molar mass.
Post your work if you get stuck.

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To calculate the number of grams of water produced from 30 g of oxygen gas, we need to first balance the chemical equation.

C6H10 + O2 --> CO2 + H2O

To balance the equation, we need to ensure that the number of atoms on both sides are equal. Let's start by balancing the carbon atoms:

C6H10 + O2 --> 6CO2 + H2O

Next, let's balance the hydrogen atoms:

C6H10 + O2 --> 6CO2 + 5H2O

Finally, let's balance the oxygen atoms:

C6H10 + 13O2 --> 6CO2 + 5H2O

Now that the equation is balanced, we can determine the molar ratios between the reactants and products. From the balanced equation, we can see that the ratio between oxygen gas (O2) and water (H2O) is 13:5.

We know that the molar mass of oxygen (O2) is 32 g/mol. Using this information, we can calculate the number of moles of oxygen gas:

30 g of oxygen gas * (1 mol of O2 / 32 g) = 0.9375 mol of O2

Now, using the molar ratio, we can calculate the number of moles of water produced:

0.9375 mol of O2 * (5 mol of H2O / 13 mol of O2) = 0.359375 mol of H2O

Finally, we can convert the moles of water to grams by multiplying by the molar mass of water. The molar mass of water (H2O) is 18 g/mol.

0.359375 mol of H2O * (18 g / mol) = 6.47 g of H2O

Therefore, the number of grams of water produced from 30 g of oxygen gas is approximately 6.47 g of H2O.