A piece of metallic iron (10 moles) was dissolved in concentrated hydrochloric acid. The reaction formed hydrogen gas and iron chloride. How many grams of HCl were consumed? Don't forget the units. Fe+2HCl---->FeCl2+H2
1. You have the balanced equation.
2. You know you start with 10 moles Fe.
3. Using the coefficients in the balanced equation, convert moles Fe to moles HCl.
4. Now convert moles HCl to grams. g = moles x molar mass.
45.3
To determine the grams of hydrochloric acid (HCl) consumed in the reaction, we need to use stoichiometry. First, we'll calculate the molar mass of HCl.
The molar mass of hydrogen (H) is approximately 1 g/mol, and the molar mass of chlorine (Cl) is approximately 35.5 g/mol. Thus, the molar mass of HCl (hydrochloric acid) is:
1 g/mol (H) + 35.5 g/mol (Cl) = 36.5 g/mol (HCl)
Next, we'll use the balanced chemical equation to find the molar ratio between iron (Fe) and HCl. From the equation:
1 mole of iron (Fe) reacts with 2 moles of HCl.
Given that we have 10 moles of iron (Fe), we can calculate the moles of HCl consumed by using the ratio:
10 moles Fe x (2 moles HCl / 1 mole Fe) = 20 moles HCl
Finally, we'll convert moles of HCl into grams using the molar mass of HCl:
20 moles HCl x 36.5 g/mol = 730 grams HCl.
Therefore, 730 grams of HCl were consumed in the reaction.
To determine the number of grams of hydrochloric acid (HCl) consumed in the reaction, we need to use the stoichiometry of the reaction. The stoichiometry tells us the molar ratio between the reactants and products.
From the balanced equation:
1 mole of Fe reacts with 2 moles of HCl to produce 1 mole of FeCl2 and 1 mole of H2.
Given that 10 moles of Fe were used in the reaction, in accordance with the stoichiometry, 10 moles of HCl were consumed.
To convert moles to grams, we need to know the molar mass of HCl.
The molar mass of HCl is approximately 36.46 g/mol (1 g/mol for hydrogen + 35.46 g/mol for chlorine).
Therefore, to calculate the mass of HCl consumed:
Mass (g) = Moles x Molar mass
Mass (g) = 10 moles x 36.46 g/mol
Mass (g) ≈ 364.6 g of HCl were consumed.
So, approximately 364.6 grams of HCl were consumed in the reaction.