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Essentials of statistics is the subject and the question is: The population of IQ scores forms a normal distribution with a mean of u=100 and a standard deviation of sigma=15. What is the probability of obtaining a sample mean greater than M=105 for a random sample of n=36 people? What is the formula in simple terms.

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    Z = (mean1 - mean2)/standard error (SE) of difference between means

    SEdiff = √(SEmean1^2 + SEmean2^2)

    SEm = SD/√(n-1)

    Since only one SD is provided, you can use just that to determine SEdiff.

    Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion corresponding the the Z score.

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