grade 12 math
posted by leanne .
solve 1tan^2x=0 , 0≤x≤2pi

1tan^2x=0
tan^2 x = 1
tan x = ±1
x = π/4, π  π/4, π + π/4, or 2π  π/4
x π/4, 3π/4, 5π/4, 7π/4
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