a mass of 0.1kg falls freely under the action of gravity .find the force acting on it its momentum kinetic energy after 10s?
The force acting on a mass freely falling, or stationary, is weight, mass*g
It does not change with time.
force=.1kg*9.8N/kg=.98N
Need
A mass of 0.1kg falls freely under the action of gravity .find the force acting on it,its momentum and kinetic energy after 10s.
Yes
A mass of 0.1 kg falls freely under the action of gravity find the force acting on it it's momentum and kinetic t after 10second
To find the force acting on the mass, we can use Newton's second law of motion, which states that force (F) is equal to the mass (m) multiplied by the acceleration (a). In this case, the mass is 0.1 kg, and since the mass is falling under gravity, the acceleration can be taken as the gravitational acceleration, which is approximately 9.8 m/s².
So, force (F) = mass (m) x acceleration (a)
= 0.1 kg x 9.8 m/s²
= 0.98 N
Hence, the force acting on the mass is 0.98 N.
To find the momentum (p), we can use the formula p = mass (m) x velocity (v). Initially, the mass is at rest (zero velocity), so the momentum is also zero.
To find the kinetic energy, we can use the formula KE = 0.5 x mass (m) x velocity^2 (v²). Initially, the mass is at rest, so the kinetic energy is zero.
However, after 10 seconds, the mass will have fallen and acquired a velocity. To find the velocity, we can use the equation of motion s = ut + 0.5at², where s is the distance fallen, u is the initial velocity (which is zero in this case), a is acceleration due to gravity (9.8 m/s²), and t is time (10 seconds).
s = 0 x 10 + 0.5 x 9.8 x (10^2)
= 0.5 x 9.8 x 100
= 490 m
The mass falls a distance of 490 meters in 10 seconds. Now, using the formula v = u + at, where v is the final velocity, u is the initial velocity (zero in this case), a is acceleration (9.8 m/s²), and t is time (10 seconds):
v = 0 + 9.8 x 10
= 98 m/s
So, the final velocity of the mass after falling for 10 seconds is 98 m/s.
Now, we can calculate the momentum:
momentum (p) = mass (m) x velocity (v)
= 0.1 kg x 98 m/s
= 9.8 kg·m/s
The momentum of the mass after 10 seconds is 9.8 kg·m/s.
To calculate the kinetic energy:
kinetic energy (KE) = 0.5 x mass (m) x velocity^2 (v²)
= 0.5 x 0.1 kg x (98 m/s)^2
= 0.5 x 0.1 kg x 9604 m²/s²
= 480.2 J
The kinetic energy of the mass after 10 seconds is approximately 480.2 Joules.