The numbers 1-10 are written on a sheet of paper and the ten sheets of paper are placed in a bowl. If one sheet of paper is selected at random from the bowl, determine the probability that the number selected is odd. (Points: 1)

Four red and seven black beans are placed into a bag. If one of the beans is selected at random, determine the odds against the bean being red. (Points: 1)

aren't there 5 odd numbers form 1 to 10 ?

so prob is 5/10 or 1/2

for the second,
prob of red is 4/11
prob of black is 7/11

odds in favour of red = (4/11) : (7/11) = 4 : 7
so odds against red = 7 : 4

To determine the probability of selecting an odd number, we need to first identify the total number of possible outcomes and then the number of favorable outcomes.

1. Total possible outcomes: Since there are 10 sheets of paper with numbers 1-10, the total number of possible outcomes is 10.

2. Favorable outcomes: Out of the 10 numbers, there are 5 odd numbers (1, 3, 5, 7, and 9). These are our favorable outcomes.

Now, we can calculate the probability:
Probability = Number of favorable outcomes / Total possible outcomes

In this case, the number of favorable outcomes is 5 (the odd numbers) and the total possible outcomes are 10 (the total number of sheets in the bowl).

Therefore, the probability of selecting an odd number is:
Probability = 5 / 10 = 0.5

So, the probability of selecting an odd number is 0.5 or 50%.