math116

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I really need help i am so stuck i can not figure this out we are trying to find the slopes here is an example of what i am doing
i get everything all theway till a certain point

example: (-4,9);2x=5y+6

the answer is 2/5x+53/5 but i don't know how they came up with 53 that is where I am getting stuckwhat are they doing to come up with that

  • math116 -

    Trudy, based on the answer you gave;
    you want to find the Eq of a line that
    passes through the given point with a
    slope = to the given Eq.

    Given: (-4 , 9) ,2X = 5Y + 6.
    2X - 5Y = 6, Slope = -A / B = -2 /-5
    2 / 5
    Y = mX + B
    Plug in the gtven point to find b:
    9 = 2 / 5(-4) + b
    solve for b:
    b = 9 + 8 / 5, 9 = 45 / 5, therefore
    b = 45 / 5 + 8 / 5 = 53 / 5.
    Eq: Y = 2/5X + 53 / 5

  • math116 -

    how did you come up with b=9+8/5,9=45/5

    you lost me there help i have five to do like this and i really am trying to under stand it

  • math116 -

    9 = 2/5 (-4) + b
    9 = -8/5 + b
    add 8/5 to each side of Eq
    8/5 + 9 = 8/5 - 8/5 + b
    8/5 +9 = b
    To add 8/5 and 9 , they should have
    a common denominator which is 5.
    8/5 +45/5 = b
    53/5 = b, or b = 53/5

    Trudy, you are having problems
    with solving basic Eq and fractions.

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