if we mix 25 g of sodium bromide with a large amount of potassium chloride, what will our theoretical yield of sodium chloride be?
NaBr+KCL->NaCl+KBr
how do you calculate theoretical yield?
soooo...would it be like this?
25gx 1mol/103g = 0.2427...
ans.x58
theoretical yield =14.0g
Why did you time is by 58? like where did the 58 come from
The stoichiometric amount of NaCl is the theoretical yield.
Convert 25 NaBr to moles. moles = grams/molar mass.
Using the coefficients in the balanced equation, convert moles NaBr to moles NaCl.
Now convert moles NaCl to grams. g = moles x molar mass. This is the theoretical yield.
NOTE: I assume you made up this problem to demonstrate theoretical yield and I have worked the problem accordingly. However, the reaction, in real practice, will NOT take place.
Yes and no.
Yes, the answer is 14 however, you have mixed up the number of significant figures. If you start with 25 g, the answer may not have more than two; therefore, 14 g is the answer in your problem.
14.2gNaCl
Well, to calculate the theoretical yield, you need to determine the limiting reactant first. And if I were to offer some chemistry humor, I would say the limiting reactant is like the strict boss who controls the reaction and only lets a certain amount of product form. But in this case, let's do the math instead of cracking jokes.
First, we need to convert the mass of sodium bromide (NaBr) to moles. The molar mass of NaBr is approximately 102.89 g/mol. So, 25 g of NaBr is equal to 25/102.89 = 0.2427 moles of NaBr.
Next, we convert the moles of NaBr to moles of NaCl. Since the stoichiometric ratio is 1:1, the moles of NaBr will be the same as the moles of NaCl.
Finally, to find the theoretical yield in grams, we multiply the moles of NaCl by its molar mass, which is roughly 58.44 g/mol. So, the theoretical yield of NaCl would be 0.2427 mol * 58.44 g/mol = 14.18 g.
Voila! That's your theoretical yield. Although, keep in mind that actual yields in the lab can vary due to various factors, including experimental conditions and the purity of the chemicals used.
To calculate the theoretical yield, you need to perform a stoichiometric calculation based on the balanced chemical equation. The balanced chemical equation you provided is:
NaBr + KCl -> NaCl + KBr
To determine the theoretical yield of sodium chloride (NaCl), follow these steps:
1. Determine the molar mass of NaBr and NaCl:
- Molar mass of NaBr:
- Na: 22.99 g/mol
- Br: 79.90 g/mol
- Total: 22.99 g/mol + 79.90 g/mol = 102.89 g/mol
- Molar mass of NaCl:
- Na: 22.99 g/mol
- Cl: 35.45 g/mol
- Total: 22.99 g/mol + 35.45 g/mol = 58.44 g/mol
2. Convert the given mass of NaBr to moles:
- Given mass of NaBr: 25 g
- Moles of NaBr = (Given mass of NaBr) / (molar mass of NaBr) = 25 g / 102.89 g/mol
3. Apply the stoichiometry of the balanced equation to determine the moles of NaCl produced from the given amount of NaBr:
- According to the balanced equation, 1 mole of NaBr reacts to form 1 mole of NaCl.
- Therefore, moles of NaCl = moles of NaBr (from step 2).
4. Convert the moles of NaCl to grams:
- Mass of NaCl = (moles of NaCl) x (molar mass of NaCl).
The result from step 4 will give you the theoretical yield of sodium chloride.