Trig-sine, cosine law
posted by Nada .
Two fire stations,P and Q,are 20 km apart. A ranger at station Q sees a fire 15.0 km away. If the angle between the line PQ and the line from P to the fire is 25degrees, how far to the nearest tenth of a kilometre, is station P from the fire?
Now this one is easy to see and draw.
direct application of cosine law,
x^2 = 20^2 + 15^2 - 2(20)(15)cos 25°
x = 9.01 km
Um the answer I was given was 5.7km or 30.5km
So how wud u get these answers?
Yup, I made a mistake, I didn't mind my P's and Q's
I now have the fire at F, and PQ=20, FQ=15 and angle QPF=25°
so we have the ambiguous case of the sine law.
let PF = x
first we have to find angle F
sinF/20 = sin25/15
sinF = .5635
angle F = 34.3° , then angle Q = 120.7
or angle F = 145.7°, then angle Q = 9.3°
x/sin 9.3 = 15/sin25
x = 5.73
x/sin120.7 = 15/sin25
x = 30.52
Thank you so much:)