algebra
posted by Joe .
Please help me factor this by grouping. I am stuck.
7x^335x^26x+30

algebra 
Quidditch
7x^3  35x^2  6x + 30
Factor 7x^2 from the first two terms and 6 from the last two terms. 
algebra 
Joe
Thank you.. SO would it be
(x5)(x+5) 
algebra 
Jen
7x^2(x5)6(x5)...

algebra 
Quidditch
Well, let's try your answer:
(x5)(x+5)
= x^2  25. So, that doesn't work.
Doing the factoring I mentioned previously gives:
7x^2(x  5)  6(x  5)
Now there are two terms. The terms have a common factor of (x5). Using our friendly distributive law we can write:
(7x^26)(x5) 
algebra 
sally
Thank you so so much for your help.

algebra 
Quidditch
Your very welcome!
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