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The half-life of radon-222 is 3.82 days. If a sample of gas contains 4.38ug of radon-222, how much will remain in the sample after 15.2 days?

  • Chemistry -

    k = 0.693/t1/2
    Substitute k into the following:
    ln(No/N) = kt
    No = 4.38 ug.
    N = solve for this.
    k from above.
    t = 15.2 days.

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