how many grams of NaOH are contained in 250 mL of a 400 M sodium hydroxide solution
moles = M x L
Then moles = grams/molar mass.
NO ANSWER
To determine the number of grams of NaOH in the given solution, we can use the equation:
molarity (M) = moles (mol) / volume (L)
Rearranging the equation, we have:
moles (mol) = molarity (M) * volume (L)
First, let's convert the given volume from milliliters (mL) to liters (L). Since 1 L is equal to 1000 mL,
Volume (L) = 250 mL / 1000 mL/L = 0.25 L
Now, we can substitute the values into the equation:
moles (mol) = 400 M * 0.25 L
moles (mol) = 100 mol
The number of moles of NaOH in the solution is 100 mol.
To convert moles to grams, we need to use the molar mass of NaOH.
The molar mass of NaOH is calculated as follows:
Molar mass (Na) + Molar mass (O) + Molar mass (H) = 22.99 g/mol + 16.00 g/mol + 1.01 g/mol = 40.00 g/mol
Multiplying the number of moles by the molar mass, we can determine the mass of NaOH:
mass (g) = moles (mol) * molar mass (g/mol)
mass (g) = 100 mol * 40.00 g/mol
mass (g) = 4000 g
Therefore, there are 4000 grams of NaOH contained in 250 mL of a 400 M sodium hydroxide solution.