Find the magnitude of the impulse delivered to a soccer ball when a player kicks it with a force of 1500 . Assume that the player's foot is in contact with the ball for 5.50×10−3
p= __kg*m/s
You need to include the units of force and seconds. I assume they are Newtons (N) and seconds, but you just can't leave out things like that in physics.
Anyway, force x time equals impulse.
Note that 1 N*s is the same as 1 kg*m/s, since 1 N = 1 kg m/s^2
To find the magnitude of the impulse delivered to the soccer ball, we can use the equation:
Impulse = Force * Time
Given:
Force = 1500 N
Time = 5.50×10^(-3) s
Substituting these values into the equation, we get:
Impulse = 1500 N * 5.50×10^(-3) s
Calculating this expression, we find:
Impulse = 8250 N·s
Therefore, the magnitude of the impulse delivered to the soccer ball is 8250 kg·m/s.
To find the magnitude of the impulse delivered to the soccer ball, we need to use the formula:
Impulse = Force * Time
Given:
Force = 1500 N
Time = 5.50 × 10^(-3) s
To get the impulse, we multiply the force by the time:
Impulse = 1500 N * 5.50 × 10^(-3) s
To get the final answer, we need to use proper units. The SI unit for impulse is kg*m/s. To convert from newtons (N) to kg*m/s, we need to use the equation:
1 N = 1 kg*m/s^2
So, by rearranging the formula:
Impulse = (1500 N * 5.50 × 10^(-3) s) / 1 N
Simplifying the equation gives us:
Impulse = (1500 N * 5.50 × 10^(-3) s) / 1
Now we can calculate the value:
Impulse = 8.25 kg*m/s
Therefore, the magnitude of the impulse delivered to the soccer ball is 8.25 kg*m/s.