Precalc
posted by Laly .
Please explain. I want to understand the steps.
1. A frog jumps from a rock to the shore of a pond. Its path is given by the equation y=(5/72)x^2+(5/3)x, where x is the horizontal distance in inches, and y is the height in inches. What is the frog's maximum height? How far had it traveled horizontally when it reached its maximum height?
2. A local bakery determines that when the price of a package of cookies is $12, it sells on average 220 packages of cookies per day. For every $0.50 increase in the price, it sells on average 10 packages of cookies less. Determine the price that maximizes the bakery's profit. Determine the maximum profit.
3.Find the quadratic function with the vertex (7,10) and with point (10,28) on its graph.

looks like you are studying quadratic function.
You should have learned a method to find the vertex of such a funtion
here is a quick way
for y = ax^2 + bx + c
the x of the vertex is b/(2a)
so in your case
x = (5/3)/(5/32) = 32/3
sub back in to get
y = 80/9
y is your height,
x is your horizontal distance
2. let the number of $0.50 increases be n
profit = (12 + .5n)(220  10n)
expand to get a quadratic, repeat the method I showed you in #1
3. let the function be
y = a(x7)^2 + 10 , in the usual vertex form
but (10,28) lies on it
so 28 = a(107)^2 + 10
solve for a, and you got it 
For 2 I did the function and got n=1. then i substitute it in and got 11.5 is that the answer? if so to which of the 2 questions?

You are right, n = 1
Since I defined n as the number of .50 "increases" we have to interpret that as a "decrease" of 50 cents.
you can verify this by making a chart
cost  number  profit
12.00 220  2640
12.50 210  2625
11.50 230  2645
11.00 240  2640
etc
so the price should be $11.50, selling 230 of them for a maximum profit of $2645
btw, (11.5 , 2645) would be the vertex of your function
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