chemistry

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When you set up the ICE chart, are you supposed to bring the 0.05 to the product side to give you an equation of x^2 / x - 0.05?

  • chemistry -

    Thomas, with the equation I gave you before you really don't need an ICE chart.
    I think I had
    Kb = (Kw/Ka) = (HC2H3O2)(OH^-)/(0.05)
    1 x 10^014/1.8 x 10^-5) = 5.55 x 10^-10
    so
    5.55 x 10^-10 = (X^2)/0.05
    Then X^2 = 5.55 x 10^-10 x 0.05
    X = sqrt(5.55 x 10^-10 x 0.05)
    This is the OH^-, convert to pOH, then to pH.

  • chemistry -

    Thank You, i got it. The answer was 8.7

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