I am having big troubles on this question.
What is the increase in acidity associated with a decrease of one unit on the pH scale?
A factor of 10.
Concn 0.1 M acidity = 10^-1 & pH = 1
Concn 0.01 M acidiity = 10^-2 & pH = 2
Concn 0.001 M acidity = 10^-3 & pH = 3
SO one unit as well? I don't really get it.
If I understand your response, absolutely not. When the acidity changes by 10, the pH changes by 1. That's what I wrote. Or said another way, when the pH decreases by 1 unit, the acidity increases by 10 units.
To determine the increase in acidity associated with a decrease of one unit on the pH scale, we need to understand how pH is defined and calculated. The pH scale is a measure of the acidity or alkalinity of a solution and ranges from 0 to 14.
The pH scale is logarithmic, which means that each whole number change on the scale represents a tenfold difference in acidity or alkalinity. When the pH decreases by one unit, it indicates that the solution has become ten times more acidic.
To calculate the increase in acidity, you can use the formula:
Acidity increase = 10^(initial pH - final pH)
Let's say the initial pH is x and the final pH is x-1. You can substitute the values into the formula to find the acidity increase:
Acidity increase = 10^(x - (x-1)) = 10^1 = 10
So, a decrease of one unit on the pH scale is associated with a tenfold increase in acidity.