How do I solve this radical equation?
3 + (2x√3) = 5
Subtract for 2x * sqrt of 3=2
Divide for x * sqrt of 3/2=1
What to do from here, I do not know. . .
it's fine i already figured it out. thank you for your help. :)
To solve the given radical equation: 3 + (2x√3) = 5, you can follow these steps:
Step 1: Subtract 3 from both sides of the equation to isolate the radical term:
3 + (2x√3) - 3 = 5 - 3
2x√3 = 2
Step 2: Divide both sides of the equation by 2 to solve for x:
(2x√3)/2 = 2/2
x√3 = 1
Step 3: To isolate x, you need to get rid of the radical (√) by squaring both sides of the equation:
(x√3)^2 = 1^2
3x^2 = 1
Step 4: Divide both sides of the equation by 3 to find the value of x:
(3x^2)/3 = 1/3
x^2 = 1/3
Step 5: To solve for x, take the square root of both sides of the equation (considering both the positive and negative roots):
√(x^2) = ±√(1/3)
x = ±√(1/3)
So, the solution for the given radical equation is x = ±√(1/3).